I know how to setup a function pointer in C.... My question is that when you make the function pointer you have to specify which parameters will be passed in....is there any way I can make this dynamic? So I could maybe do something like this: void Blah(char *parseMe) { // parse the string...but how? } FunctionPointer = Blah FunctionPointer("%d %d", variableOne, variableTwo); Without having to specify that the function pointer will need two integers passed in?

i think the only way to do that would be to declare a variable arg function and ptr,

void MyFunc(...){    //do your func here    //using the va_start, va_end}void FuncPtr*(...);   //syntax correct?  i always have to look.FuncPtr = MyFunc;FuncPtr( arg1, arg2, arg3 ); 

but that may have significant overhead.
good luck

crazy166
some people think i''m crazy, some people know i am

doh! i see where you''re going.

yes, use variable arguments like so:

void MyFunc( char* string, ... ){} 

and your code will work. unsure of parsing, though. look up va_start, va_end, va_list in some C or C++ reference.

Another idea is to make your function pointer point to a function that takes a single void* parameter, which could then be used to pass the address of a structure containing any number of parameters.

For example:

  // function pointertypedef void(*FuncPtr)(void*);// function which takes one input and gives one outputvoid Double(void* parms){	typedef struct{int in,out;}Parms;	Parms* p = (Parms*)parms;	p->out = (p->in*2);}// function which takes two input2 and gives one outputvoid Add(void* parms){	typedef struct{int in1,in2,out;}Parms;	Parms* p = (Parms*)parms;	p->out = p->in1 + p->in2;}int main(){	int result;	FuncPtr fp;	{		typedef struct{int in,out;}Parms;		Parms parms = {10,0};		fp = Double;		fp(&parms);		result = parms.out;	}	{		typedef struct{int in1,in2,out;}Parms;		Parms parms = {10,20,0};		fp = Add;		fp(&parms);		result = parms.out;	}	return 0;}  

Whilst this may not be the best way to go about your problem, it is a solution.

Andy.