could someone please refresh my memory on how to pass a multi-dimensional array to a function as a referance parameter (C++) thanx

Uhh, I''d just pass a pointer to the array. You can easily access all the array elements (even in a multidimensional array) through the pointer. I was taught early on that it''s generally a bad idea to send an array, especially a multidimensional array to a function as it will then push the entire array onto the stack. Not to metion it''s just bad form, and real programmers will make fun of you I''m still a relatively new programmer, so I could be wrong.

you mean
int** &Array2DReference
?

OK, here we go....

int nums [3][4];

int *pnum;

pnum=#//OK this points to index nums[0][0]


void doit(int *pnum)
{
cout<<*pnum[2][1];//Print the value at nums[2][1]
}

You can access any value in the array by indexing it like a standard array. You can go further and just make the array a pointer in the first place.

int *nums [3][4];

Like I said though, I''m new, I could be wrong. Someone feel free to correct me

Pretty much. The reference I have says that

function(int a[]);

is the same as

function(int* a);

thanks for the help everyone.