You don''t really need to do anything. Take this class for example (I''ll use a static array, but it will work the same with dynamic arrays as long as you allocate them properly, and not in the array-of-pointers-to-array method): class Foo { private: int data[100][100]; public: int* operator[](int i) { return(data); } }; That''s all you need. When you try to do the following: Foo bar; int x = bar[10][20]; the operator[] function returns the address of bar[10] and then dereferences that address + 20. Like ((int*)bar[10])[20]. You can think of it like this: Foo bar; int* ptr; int x; ptr = bar[10]; x = ptr[20]; But it does it all in one quick step.

What's the meaning of this post ?

Why, if one ever uses static arrays, create a class for it ?
And if creating a class, why not make it dynamic for reusability ?

And, btw, The [] was cut out of your code because I is for italic fontset

     class Foo {  private:   int data[100][100];   //  public:   inline int *operator[](int num) {     return(data[num]);   } };    

-Markus-


Edited by - Cygon on September 29, 2000 4:17:24 PM