// function
void somefunc (const A& obj)
{
//stuff
}
void main ()
{
B ihopethisworks;
somefunc (ihopethisworks::A);
}
If this is not the way to do it, is there a way at all??
C++ quickie.
Say I have a class A and a class derived from A called B.
(ie. class A; class B : public A
I have a function that accepts a const A&, now I know that B is a type of A, so is there a way I can use an object of B as a paramter to this function?
Here''s my guess as to how to do it:
--------------------------I guess this is where most people put a famous quote..."Everything is funnier with monkey''s" - Unknown
You should just be able to do:
JoeDark
class A {};class B : public A {};void somefunc(const A &obj){}void main(){ B an_object; somefunc(an_object);}
JoeDark
Oh.
Thats unexpected.
If the function took a the full object and not just a reference that wouldn''t work right?
Thats unexpected.
If the function took a the full object and not just a reference that wouldn''t work right?
--------------------------I guess this is where most people put a famous quote..."Everything is funnier with monkey''s" - Unknown
quote: Original post by Promiscuous Robot
Thats unexpected.
Actually it's not. Object B "ISA" Object A. Your function takes objects of type A. Since B is an A then there's no problem.
quote:
If the function took a the full object and not just a reference that wouldn't work right?
Same deal. Object B is of type A so the function sees it as type A.
-------
Andrew
Edited by - acraig on January 26, 2001 8:01:42 PM
This topic is closed to new replies.
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