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strings...damn them

Joker2000 · 2000-07-11T06:04:39

Ok, this issue is REALLY starting to piss me off! I can't seem to grasp the concept of strings. First of all, is the datatype "string" the same as "char *" ? Well, of course I know that they're not the same, but are they similar (i.e. do they do the same thing)? Maybe it would be best to put this in an example. I'm creating a small console game that asks a user to type in the name of their player. I'm going to store this name in the string variable name. However, the name can't be more than 30 characters. Here's what I have so far (this is of course a brief snippet): void create_new_player() { string name; cout << "Enter the name of your player."; cin >> name; if (strlen(name) > 30) // is this correct strlen syntax? cout << "Name too long. else player p1(name, 100, 0,0) // creates p1 using class "player" } However, if I use the code just as I have entered it above, I get errors dealing with the strlen function: Could not find a match for 'std::strlen(std::basic_string,std::allocator >)'. I have tried other syntax structures such as: strlen.name() strlen(&name) strlen.*name() strlen.*name ...etc etc etc... I have also tried declaring "name" as "char *name" but still it doesn't work. Why is this not working? Please help! BTW, I'm using Borland C++Builder 3.0, if it makes a difference. Blake Young Edited by - Joker2000 on 7/5/00 3:20:18 PM Edited by - Joker2000 on 7/5/00 3:21:15 PM

General and Gameplay Programming Programming

Started by Joker2000 July 05, 2000 03:18 PM

34 comments, last by Joker2000 24 years, 5 months ago

bishop_pass

112

July 11, 2000 12:21 AM

By the way, this is perfectly legal in any C variation:

char something[50] = { ''S'', ''t'', ''r'', ''i'', ''n'', ''g'', ''s'' };

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Anonymous

July 11, 2000 12:27 AM

vbisme, the reason your code doesn''t work is because myString isn''t a char, it''s a char*. Therefore if you change your GetmyString() to this:

    char* Test::GetmyString(){    return (myString);}

it will work.

bishop_pass

112

July 11, 2000 12:28 AM

Ha!

I just consulted a book on valid C syntax.
This is legal. If it doesn''t work, then your compiler sucks because it doesn''t recognize valid syntax.

char something[50] = "Strings";

vbisme

100

July 11, 2000 01:03 AM

if...:
class Test
{
private:
char myString;

char *Test::GetmyString()
{
return (mySring);
}

Compiler Error: cannot convert from ''char[50]'' to ''char[]''

Anonymous

July 11, 2000 01:39 AM

vbisme,

What compiler are you using? What are the settings?

Try this:

    class Test{private:    char myString;    char* Test::GetmyString()    {        return (char*)(mySring);    }};

Although I''m not quite sure why it''s giving that error.

CMN

122

July 11, 2000 06:04 AM

When working with strings, strcpy is the way to go...

/CMN

strings...damn them

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