does the AddIt() function work with vc++6? cuz im getting errors, with it. SKATEBOARDING IS NOT A CRIME!

Never heard about that function.

I think you just made it up;
maybe its a function he found in a tutorial. In that case, killadude, you have to define it first.

"I''ve learned something today: It doesn''t matter if you''re white, or if you''re black...the only color that REALLY matters is green"
-Peter Griffin

in my book "teach yourself c++ in 21 days"
it uses addit like this
#include <iostream.h>

void main()
{
int iNum1;
int iNum2;
int iResult;

iResult = AddIt(iNum1, iNum2)

cout<<"The result is: \n";
cout<< iResult;
cout<<"\n";
}

SKATEBOARDING IS NOT A CRIME!

Result = Num1 + Num2;

thanks fruny- but i already know that, i was just askin if that function really worked or was it just lack of knowlege of the author of the book, but thanks for your post

SKATEBOARDING IS NOT A CRIME!

Frankly, I don''t trust those "learn in days" books. I find it''s more of a gimic to sell the book, and any book that needs a gimicky name is a suspicious one (see also Books for Dummies).

"I''''m not evil... I just use the power of good in evil ways."

To answer your question, no, it's not a function. The author probably defined it somewhere in a previous chapter.

if for some reason it is an oversight (if it is i would put down the book and look elsewhere to learn c++ =) ) it's probably defined like this:

    #include <iostream.h>int AddIt(int num1, int num2){    return num1 + num2;}void main(){    int iNum1;    int iNum2;    int iResult;    iResult = AddIt(iNum1, iNum2)    cout<<"The result is: \n";    cout<< iResult;    cout<<"\n";}     

Edited by - AbsolutDew on February 5, 2002 3:13:51 AM

quote: Original post by Tac-Tics
Frankly, I don''t trust those "learn in days" books. I find it''s more of a gimic to sell the book, and any book that needs a gimicky name is a suspicious one (see also Books for Dummies).

"optimised ultra sparc assembly for dummies"


Beer - the love catalyst
good ol'' homepage

Well, it most certainly must be a function (or a function-like macro), otherwise any source file referencing it wouldn''t compile without at least a warning. But, of course it''s not a standard function.