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Potentual new concept

Donnie Watson · 2015-11-08T23:18:49

Hi all, I would like to introduce an abstract Concept into the A.I. and Gaming community.My only qualification is perception.I precieved the idea of a new concept there fore am qualified. This being said;,I, really need a professional to understand,interpite,develope,and verify it'spotentual. My belief is that it will introduce logic,and relitivity to programming;,Not,As a fast action,but,as an efficient over all learning process. Just as A.I. learns with repatition this could be used to relate logics,and relations over time.My introduction to the abstract concept begins with the observations which lead me to it.This is important to show the facts from the abstract usses. 1. Parrallel resistance A. effectiveParll_restance= 1 / ((1/r1)+(1/r2)+(1/r3)---) a1. effectiveParll_restance is always less than least resistor. a2. Before the last {1/} the sum is always intuativly a unique extension to the vector length. ie. .5+.25+.25 +.125=1.125 a3 The {{ effective_resistance is relitive to the lost_resistance and the total_resistance ie; effective_resistance = Total +(lost*-1) }} ie; 0.625= 1.125+((.25+.25)*-1) == .5 +.125 a4. Abstract: if resistance is an asc(code) ie:asc(*) is 49, then the total of "country United States" is relitive to " United " = { "country United States" + (("country +States" )*-1) B. Parrallel resistance program_loop format. b1. Stream$="800 96 50 12" total=val(Stream$,x) loop x=x+1 r=val(Stream$,x) total=(1/ (r*(1/total)+1)))*r next loop note total=8.69565217 == 1/((1/800)+(1/96)+(1/50)+(1/12)) ABSTRACT: b1a. Observe the percentage relation r*%= effective_total b1b .Observe A= atn(%) A1 A2 A3 final A =A3 Note that r(n)= total(n)*(1/tan(A(n))) or T(n)=R(n)*(1/tan(A(n)) final total=final total This is where logic_relative_addressing and relative_logic comes into play. Abstract:: A Abstract relitive logic 1. P>0 .5 2. P<0 * .25 3. H=0 .136 4. H>0 * .33P<0 5. P=1 .4 total = 1.616 6. Abstract relitive logic mixer : ( {1.616 - 1.036 = .58} *-1) + relitive total == 13 == " P<0 , H>0 " == "quadrent 2" B Abstract relitive addressing 1 Page unique_code = 0.02425 2 Options unique_code total = 0.325 3 address is 0.30075= 0.325+(0.02425*-1) 4 action== goto "[";"0.30075";"]" == goto [0.30075]'***************************[0.30075]open "page25.txt"return C Note the action is based on relations of content not on the content. ie; the action is assigned thru the relations that define it. Heavy concept?? yes!No one said dealing with logic,relitivity,reasoning,and selfawarness was simple.BUT YOU NEED TO START SOME WHERE. To understand it. I believe this to be the starting place.I need help proving it.This is only an incomplete glimps at the detail. '******************************************************************** SHOWING WHERE T AND A ENTER THE EQUATION:: Pr=1e100 {T(1),A(1)} {T(2),A(2)} {T(3),A(3)} {T(4),A(4)} Not in Formula form Pr=(1/1e100) (1/800) + (1/96) + (1/50) + (1/12) '******************************************************************** Pr=1e100 'initialize 'Abstract T T=Pr A=45 'initialize { relativity } { Pr) {T} %= 1 / ((800*(1/1e100)) +1) Angle=atn(%) 'Abstract A(0) -- Angle T=800*tan(A) 'Abstract T(0) Pr(1)=T -- total(0) T(1)=800 A(1)= 1 / ((800*(1/1e100)) +1) Angle=atn(%) 'Abstract A(0) -- Angle T(0)=800 'Abstract T(0) == Pr(0)=T -- total (0) A(0)=45 {{ 'initialize complete}}' '@@@@@@@@@@@@@@@@@@@ [loop]{1} { Pr} {T} '''''/%= 1 / ((800*(1/800)) +1) ''''/ Angle=atn(%) 'Abstract A(0) -- Angle T=800*tan(A) 'Abstract T(0) Pr(0)=T -- total T in Program form T(1)=800 %(1)= 1 / ((800*(1/800)) +1) Angle=atn(%) 'Abstract A(1) -- Angle A in Program form T(1)=400 A(1)=26.565051177077989351572193720453 next [loop]'@@@@@@@@@@@@@@@@@@@ [loop]{2} { Pr} {T} ''''/%= 1 / ((96*(1/800)) +1) ''''/Angle=atn(%) 'Abstract A(2) -- Angle T=96*tan(A) 'Abstract T(2) Pr(2)=T -- total T(2)=85.714285714285714285714285714286 %(1)= 1 / ((96*(1/800)) +1) Angle=atn(%) 'Abstract A(2) -- Angle T(2)=400 A(2)=41.760299703897870309452138780517 next [loop]'*********************************************************************************************** With T and A in the equation it is concievable to back_track the process. ie; T=Pr*tan(A) and Pr=T*(1/tan(A)) '@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@Now the hard part.. This is the relitivity system.The SYSTEM that makes the Final_Code {FCode} relavent. Pi=atn(1)*4:Mdeg=(180/Pi):Mrdn=(Pi/180) DL$="800 96 50 12 3 7 18 21 41 45 96 50 12 3 7 18 800 96 50 12 3 7 18 21 41 21 41 45 96 50 12 3 7" Pr=val(word$(DL$,1)):F=Pr Pr=1e-100 for j=1 to Lng(DL$) R=val(word$(DL$,j)) FCode=FCode+((1/R)+(1/A)) gosub gosub [Decode] next j print eDL$ print FCode end 'print R c=abs(1/(R*(Pi^2))) c1=c Pr=F A=atn((1/((R*(1/F))+1)))*Mdeg L=(A*(1/(Pi^2))) F1=1/(((L*c)^.5)*(2*Pi)) Pr=R*tan(A*Mrdn) 'print Pr return [Decode] print R c=abs(1/(R*(Pi^2))) c2=c F2=1/(((L*c)^.5)*(2*Pi)) 'L2=((1/F2)/(2*Pi))/c2 F=(1/((1/tan(A*Mrdn))-1))*R A2=L*(Pi^2) D=Pr*(1/tan(A*Mrdn)):eDL$=eDL$;str$(int(D));" " 'print tab(16);D;" ";F1+(F*-1);" ";A2+(A*-1) return'@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@@ The relivence of the FCode is the logic of the system. Rule is {relitive to the system} FCode of "one apple = 35 cars" = only "one apple = 35 cars" Therefore box_Fcode is the same as box_"one apple = 35 cars" ;, But , box_Fcode + box_Fcode2 is _"one apple = 35 cars" + box_something else. ie; "P<0" + "H<0"= "Quadrent 2" How???? assigned logic --- if Code(1) + Code(2)= 0.73433 then GOTO= { Code= (Code(1) + Code(2) +Code(3) ) + ((Code(1) + Code(2))*-1) } if GOTO= ? then print "Quadrent 2" Now where we used resistance before;,We, can use coded logics and relate them as effective_Logic= 1/ ( (1/EL1) + (1/EL2) + (1/EL3) --)) or Gain=(Total+(Loss*-1)) The difference is that these are assigned abstract relitive relations {relitive to the rule of the abstract System} Now we can assign logics,relations,relitivity,reasoning,creativity, ect -- as temporary or constants.At {LEAST} it is a start at understanding how it works. If interested My e-mail is [deleted by moderator]

GDNet Lounge Community

Started by Onedream September 10, 2015 03:07 PM

98 comments, last by TheComet 8 years, 10 months ago

Norman Barrows

7,180

September 12, 2015 06:07 PM

for those who might be curious, here's the formula for parallel resistance. i learned this in 2nd year electronics shop in 10th grade in high school in 1978 - the same year i wrote a turn based clone of lunar lander for the IBM 360 mainframe in basic on a 1200 baud dumb terminal in computer class:

http://physics.bu.edu/py106/notes/Circuits.html

https://en.wikipedia.org/wiki/Series_and_parallel_circuits

Norm Barrows

Rockland Software Productions

"Building PC games since 1989"

rocklandsoftware.net

PLAY CAVEMAN NOW!

http://rocklandsoftware.net/beta.php

Onedream

Author

120

September 13, 2015 02:15 PM

What is a relitive address?

Think of it as a starting address.

address 0.657444

contents ooo1ooo oo1o1oo o111111o o1ooooo1o

the contents defined the address.this is what makes it relitive.

Uses are

A. address(1) "distance"

+ address2) "angle of rotation

+ address(3) "angle of elevation

= relation(1) total potentual logic = "distance angle of rotation angle of elevation

1 and 2 = "distance angle of rotation"

1 and 3 = "distance angle of elevation Two clearly difference logics.

B BUSCUITS ingrediance 1 ingrediance 2

1 water 1 sugar yeast

2 baking powder 2 baking powder chilli

3 salt 3 flour salt

4 flour 4 corn mill egg

5 water

2,3,5 3 = 2,3,5,3

What logics does that tell me.

A 3 ingrediance needed in list 1 and 1 in list 2

B I need both lists to make BUSCUITS

C there is no specific order. ie: address- "water baking powder salt flour" is not equal to address- "baking powder flour water salt"

Is this a clue to thought,thinking,reasoning, ect??

Waterlimon

4,401

September 13, 2015 03:28 PM

This very much resembles "hashing". You take an object, and run it through some complicated math to get its hash, which is basically an integer of finite size. Same object always gives the same hash (for a given algorithm). Sometimes, two different objects have same hash, but this is rare (since they are distributed randomly in the space of all possible hashes)

Is your "address" the same as "hash"?

o3o

Onedream

Author

120

September 13, 2015 04:53 PM

Waterlimon,

I would guess yes.

The exception being that the {order} is part of the process.

ie; abc is different than bac

This is due to the frequency,resistor,and angle are relevant to each other.

This makes it unique.

example

R=A=T=R=A=T and address +address = ((1/R)+(1/A)) = unique address.

As proof ??

List of T's and list of A's reproduce original content and order.

and the final T and final A does the same.{in theory}

d000hg

1,208

September 14, 2015 08:04 AM

By the time I looked all the spelling up,I'd be dead.LOL

Or you could use spell check.

But he lays his words out in such a pretty way. Got to get some credit for that.

Onedream

Author

120

September 14, 2015 08:12 PM

My last post unless there are questions.

This is what I know and speculate.

It is simple enough.

r1=800 r2=96 r3=50 r4=12

{T} {D}

1/((1/800)+(1/96))=85.714286 {1/((1/800)+(1/96))}

{D} {T} {next T}

[1/ ((96*(1/800))+1)]*96=85.714286

1/((1/85.714286)+(1/50))=31.578947 {1/((1/800)+(1/96)+(1/50))}

[1/ ((50*(1/85.714286))+1)]*50=31.578947

1/((1/31.578947)+(1/12))=8.6956522 == effective r {1/((1/800)+(1/96)+(1/50)+(1/12))}

[1/ ((12*(1/31.578947))+1)]*12=8.6956522 == effective r

True or Faulse ?? ^^

now

[1/ ((96*(1/800))+1)]=0.892857 always a % of r.

ie, 96*0.892857 =T

So the % can relate to an angle. ie;A=atn(%)

Note: Nothing has changed except my logic. T=96*tan(A)

True or Faulse ?? ^^

*********************************************************************************

What are my possable back tracking formula?

T=R*% vs R=T*(1/%)

T=R*tan(A) vs R=T*(1/tan(A))

last T=1/((1/tan(A))-1)*R vs last T= 1/((1/%)-1)*R

A=atn(T/R) vs %=T/R

True or Faulse ?? ^^

'********************************************************************************

How do I back track the entire thing?

A=final A==35.928502

T=final T==0.892857

R=T*(1/tan(A))=12

last T=1/((1/tan(A))-1)*R == 31.578947

last A= unk

last R= unk

back track ended.

True or Faulse ?? ^^

'*******************************************************************************

Wait I have last T so if I get last A I can continue back track

ie;last R=last T*(1/tan(last A))

'@@@@ A little abstract logic to pass last A

'********************************************************************************

Frq of resonance = 1/(sqr(L*c)*(2*Pi))

if R is always an interiger and I tack (1/T) as the fraction I maintain R and T

if I create c with R and L with A and replace T with F then I can still back track int(R) ???

note: My focuse is on R so I care not that T is F

R=R+(1/T)

c=1/(R*(2Pi)^2)

L=A*(1/((2Pi)^2)

F=1/(sqr(L*c)*(2*Pi)) T=((1/R)+1/F))

last F=1/((1/tan(A))-1)*R

L= sqr((1/F)/(2*Pi))/c

last A=L*((2Pi)^2)

last R=last F*(1/tan(last A)) R=int(R)

note {in theory} there is an accumulated accuracy problem.

{in theory} I can back track.

True or Faulse ?? ^^

'********************************************************************************

Due to the inter action of R,T,and F

R and A are unique so the sum of ((1/R)+(1/T)) is unique.

This is the relative address.

It doesn't have to be accurate,just unique to the input.

True or Faulse ?? ^^

'*******************************************************************************

if each address is unique then the total,gain,and loss of a group of addresses is unique.

note leave addresses as fractions.

such that; addr1+addr2+addr3==:total is fraction

ie; ((1/addr1)+(1/addr2)+(1/addr3))=total is fraction

The primary logic now is total=(gain+loss), gain=total-loss,and loss=total-gain.

P<0

H>0

total=addrT == P<0 and H>0

gain=addrG == P<0 H>0

loss=addrL == and

one possable redirect.

relitive redirect depended of the relation defined {ie function relation(,,,) }

total=addrT+addrT2 == P<0 and H>0 Quadrent2

gain=addrG == Quadrent2

loss=addrL == P<0 and H>0

think?? if T=val(word$(stream$,addrn) then print word$(target$,addrx)

The question is;

Is this a tool to deal with real logic, not formulated logic??

Onedream

Author

120

September 16, 2015 08:25 PM

'I forgot to mention this part.

'This is an important part of the concept.

'and I don't know how to explain it.

'But it completes the relitive address.

'type common extention ==IconCd {relitive address}

'Relitive relations:{related by way of the functions} They are all relitive_Icons

'A File will not find a Label

'A File bmp will not find a File txt

'ect

'example--- Stream$="birds fly" ,Stream$="Tweety is a bird" ,Stream$="Tweety flies"

'Stream$="Tweety is a penguin"

'example--- Group$="Statement" Type$="Truth Truth Hypothasis False"

'example--- Group$="logic";"File" '"Label" Relitive_String is "logic0.xxxxx"

'example--- Type$="Code","bmp" '"txt" Relitive_String is "Code0.xxxxx.bmp"

[EnterLogics]

print tab(4);"AddressStream";tab(38);"Address";tab(56);"Logic"

[backtorespond0]

Respond$=""

prompt "Logic Stream$";Respond$

Stream$=Respond$

if Respond$="" then [backtorespond0]

if Respond$="e" then end

LogicStreamin$=Stream$

[backtorespond1]

Respond$=""

prompt "Group"; Respond$

Group$=Respond$

if Respond$="" then [backtorespond1]

if Respond$="e" then end

[backtorespond2]

Respond$=""

prompt "Type";Respond$

Type$=".";Respond$

if Respond$="" then [backtorespond2]

if Respond$="e" then end

gosub [RelitiveCode]

print tab(38);RelitiveCode;tab(56);LogicStreamin$

goto [backtorespond0]

[quit]

end

[RelitiveCode]

Prefx$=Group$

Profx$=Type$

'print CoderCd(Stream$)

RelitiveCode=IconCd(Prefx$,Profx$,Stream$)

return

'*********************************

Function IconCd(Prefx$,Profx$,byref Stream$)

Stream$=Stream$;Prefx$;CoderCd(Stream$);Profx$

AddressStream$=Stream$:print tab(3);AddressStream$;

IconCd=CoderCd(Stream$)

end function

'*********************************

Function CoderCd(byref Stream$)

Pi=atn(1)*4:Mdeg=(180/Pi):Mrdn=(Pi/180)

Pr=1e-100:A=45

Pr=asc(mid$(Stream$,1,1)):F=Pr

for j=1 to Len(Stream$)

R=asc(mid$(Stream$,j,1))

CoderCd=CoderCd+((1/R)+(1/A))

'print R\par

c=abs(1/(R*(Pi^2)))

c1=c

Pr=F

A=atn((1/((R*(1/F))+1)))*Mdeg

CoderCd=CoderCd+((1/R)+(1/A))

L=(A*(1/(Pi^2)))

F1=1/(((L*c)^.5)*(2*Pi))

Pr=R*tan(A*Mrdn)

'print Pr\par

next j

Stream$=""

end function

INPUTs

Tweety flies Stat1 true

Tweety is a bird Stat1 true

Tweety is a penquin Stat1 faulse

Tweety is not a penquin Stat1 true

flies stat2 hyp

OUTPUTs

AddressStream Address Logic

Stat1.23036312.true 1.94293624 Tweety flies

stat1.67359094.truth 1.88191062 Tweety is a bird

stat1.98701172.faulse 1.97451554 Tweety is a penquin

stat2.41767995.truth 1.87900211 Tweety is not a penquin

Total=7.67836451

Parrell total=2.0847105177768540224003228826394

stat0.46000944.hyp 1.70362044 flies

Total=9.38198495

Parrell total=2.6716957267592022266752140667343

I'm no math person,but something like this may be a good application of relitive addresses.

{Just a thought}

Default Logics

total-loss 1 total-loss gian 1

----------- / ---- = ---------- * ----- = --- = "Tweety flies is true"

gain gian gian 1 1

ie;

1/9.38198495-1/1.94293624 1

--------------------- / ----

1/1.70362044 1/1.70362044

Aardvajk

13,217

September 17, 2015 07:40 AM

I have the definite impression you are expressing something very simple in a very complicated way. That is the precise opposite of the skill you need to get an idea off the ground and discussed.

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