Don''t know if it helps... but maybe this is what you''re looking for.

int b[2][2] = { 0, 0, 0, 0 };
int *pb = b[0];

Now I could do:

pb[0] = 1;
pb[1] = 2;
pb[2] = 3;
pb[3] = 4;

printf("b[0][0] = %i\nb[0][1] = %i\nb[1][0] = %i\nb[1][1] = %i", b[0][0], b[0][1], b[1][0], b[1][1]);

The output would be:

b[0][0] = 1
b[0][1] = 2
b[1][0] = 3
b[1][1] = 4

Is that what you''re trying to do? You could multiply the array indices to get the index to use with the pointer quite easily.

Good luck

Starfall