Can someone suggest a quick way of determining if a number is off or even. My first thought was to divide by 2 and see if there is a leftover. I''m sure though you could do a boolean test on the last bit or something like that... Suggestions Thanks Chris

if (value & 0x01) then odd.

Thanks.. That did the trick

Another way is:

if ((value % 2) == 0) // evenelse // odd

That''s just my way...