I can create a new terminal using Alt+Ctrl+Shift+Fn. However, how do I kill it? Thanks in advance.

I think you may be slightly confused.
Usually when you start up a *nix machine and enter the first console, the others are started automatically.
All Alt-Ctrl-Shift-Fn (Or variation of such) does is switch between the other consoles that are allready running rather then creating a new one.
Now if you wish to actually have less consoles starting up and get rid of them completely, (carefully!) edit your inittab file and look for the consoles section.
Mine looks like this:

# TERMINALSc1:12345:respawn:/sbin/agetty 38400 tty1 linuxc2:2345:respawn:/sbin/agetty 38400 tty2 linuxc3:2345:respawn:/sbin/agetty 38400 tty3 linuxc4:2345:respawn:/sbin/agetty 38400 tty4 linuxc5:2345:respawn:/sbin/agetty 38400 tty5 linuxc6:2345:respawn:/sbin/agetty 38400 tty6 linux

If i wanted to get rid of the last one i would simply comment it out, for example:

# TERMINALSc1:12345:respawn:/sbin/agetty 38400 tty1 linuxc2:2345:respawn:/sbin/agetty 38400 tty2 linuxc3:2345:respawn:/sbin/agetty 38400 tty3 linuxc4:2345:respawn:/sbin/agetty 38400 tty4 linuxc5:2345:respawn:/sbin/agetty 38400 tty5 linux#c6:2345:respawn:/sbin/agetty 38400 tty6 linux

I'm not too familar with the formatting of inittab, but i do know the second column of numbers (i.e 12345) is which run levels these consoles should spawn in. So in the first example, only the first console would be active on the first run level, while on run levels 2-5, all of them would be active.

Also note I'm running a Gentoo machine so my inittab prolly looks slightly different then say a RedHat machine.
I hope this answers your question.