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Compile Error in g++

Started by May 04, 2005 01:48 AM
4 comments, last by GameDev.net 19 years, 6 months ago
The following code compiles fine in msvc++ but produces errors in g++, does anyone know of a workaround?

template<class T> class A
{
     void foo(void)
     {
         for(list<T*>::iterator i = m_List.begin(); i != m_List.end(); ++i)
             (...)
     }

     list<T*> m_List;
};
The problem seems to be with the declaration of i. Is this a known bug in g++?
template<class T> class A{     void foo(void)     {         for(typename list<T*>::iterator i = m_List.begin(); i != m_List.end(); ++i)             (...)     }     list<T*> m_List;};
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Thanks alot, worked perfectly.
When you're implicitly creating a type from a template parameter eg: std::list::iterator you need to tell the compiler that it's a type using the typename keyword, otherwise it gets confused and throws an error. I've fallen foul of this a few times in GCC, MSVC always used to handle it fine.
Note that MSVC++ is just trying to being nice to you there -- the standard requires the typename. Some versions of G++ will give you an "implicit typename is deprecated" warning, however, and compile properly if it correctly guesses it's a type. Don't count on it for long though -- the support of implicit typenames wont be included in the next version, iirc.
Quote: Original post by me22
Note that MSVC++ is just trying to being nice to you there....


That's the kind of "help" no sane person would like. Thanks MSVC for helping us write broken code.

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