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Turning a member of a string to an integer?

Started by July 13, 2000 11:35 PM
4 comments, last by SpikyQube 24 years, 5 months ago
This is bothering me, How do I turn a member of a string to an integer, let''s say: char string1[9]; int number; scanf("%s", string1); some people might type in something like "hello", which is a string, but others might and will type in 5, or 6, or a number. So basically string1[0] is a number, but in string format. How do I like convert it into an integer format (store the value in number) without change its value? Like if someone type in a 6, and I do: printf("%d\n", number) It''ll like display 6, ya know? Thanx I want to work for Squaresoft ;)
I want to work for Squaresoft ;)
Convert it to an integer..

If you have:

char number[] = "32768"; // Number as text..

then you can say:

int n;
sscanf(number, "%d", &n);
printf("The number is %d\n", n);

Or, use the C-Runtime function atoi() (ascii to integer)

int n;
n = atoi(number);
printf("The number is %d\n", n);


Hope that helps..

// CHRIS
// CHRIS [win32mfc]
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AWWWW, I need to familiarize myself with the standard C library!!! That will be my goal for the next few weeks, hehe...

Thanks for the help man! I greatly appreciated

I want to work for Squaresoft ;)
I want to work for Squaresoft ;)
Let this be a testament to the dangers of self education:
I never knew about atoi(), I actually wrote my own function to do this..I felt pretty good at the time, now I feel sort of ridiculous ..you can all start laughing now..

"Like all good things, it starts with a monkey.."
"Like all good things, it starts with a monkey.."
you can also do..

scanf("%s", string1);
printf("The first number is %d", (int) string1[0]-''0'');


..-=gLaDiAtOr=-..
The ato* functions are unreliable. They return 0 if they can''t successfuly convert the given string to a number. So there''s no way of determining if the user entered "0" or an invalid number. Use sscanf instead.

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