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Derivatives
Determine Dx Y
1. y = sin^2x + sinx^2
2. y = log(4x^2 + 1)
Thanks
[edited by - Gimlin on June 18, 2003 5:15:00 PM]
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June 18, 2003 04:45 PM
I got the first one, if anyone cares its
y = sinx * sinx + sinx ^2
y''= sinxcosx + sinxcosx + cosx * 2x
y''= 2sinxcosx + 2xcosx
since sin2x = 2sinxcosx
y''= sin2x + 2xcosx.
y = sinx * sinx + sinx ^2
y''= sinxcosx + sinxcosx + cosx * 2x
y''= 2sinxcosx + 2xcosx
since sin2x = 2sinxcosx
y''= sin2x + 2xcosx.
y = log(4x^2 + 1) (I''m assuming the log is base 10)
y'' = 8x / [(4x^2 + 1) * ln(10)].
"If I only had 6 months left to live I''d get back together with my first wife,
because 6 months with her would be like an eternity."
-Bobby Hall
y'' = 8x / [(4x^2 + 1) * ln(10)].
"If I only had 6 months left to live I''d get back together with my first wife,
because 6 months with her would be like an eternity."
-Bobby Hall
"If I only had 6 months left to live I'd get back together with my first wife, because 6 months with her would be like an eternity." -Bobby Hall
Lucky you no moderator saw this homework thread before you got the answers...
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____________________ ____ ___ __ _
Enselic''s Corner - My site. Go test my game Spatra and see if you can beat it onto the Official Spatra Top 10. (source available)
CodeSampler.com - Great site with source for specific tasks in DirectX and OpenGL.
[s]--------------------------------------------------------[/s]chromecode.com - software with source code
June 18, 2003 06:15 PM
assuming that:
sin^2x means sin^2(x) AND
sinx^2 means sin(x^2)
then the first part of #1 is as above (sin[2x]), but the second part is actually:
sin(x^2) --> 2x*cos(x^2) AND NOT 2x*cos(x)
sin^2x means sin^2(x) AND
sinx^2 means sin(x^2)
then the first part of #1 is as above (sin[2x]), but the second part is actually:
sin(x^2) --> 2x*cos(x^2) AND NOT 2x*cos(x)
For future reference, homework questions are strictly prohibited unless they relate to game development AND you''ve shown some personal attempt.
June 18, 2003 06:26 PM
acctually they are practice questions for my exam tomorrow. I have the answers. I needed to know how to do the questions.
I'm sure there are forums which are meant for this sort of thing. I know NRICH does up to a certain level.
http://www.nrich.maths.org.uk/
I'm not sure if it would be suitable or not, but you can always check it out. There will be american ones as well. They will help with homework, but in a constructive manner.
[edited by - higherspeed on June 19, 2003 6:06:55 AM]
http://www.nrich.maths.org.uk/
I'm not sure if it would be suitable or not, but you can always check it out. There will be american ones as well. They will help with homework, but in a constructive manner.
[edited by - higherspeed on June 19, 2003 6:06:55 AM]
This must be homework. Thread closing now.
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Graham Rhodes
Senior Scientist
Applied Research Associates, Inc.
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Graham Rhodes
Senior Scientist
Applied Research Associates, Inc.
Graham Rhodes Moderator, Math & Physics forum @ gamedev.net
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