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Latest Largrangeequations Activity

@jak6jak Sorry, my net was down - and I was too busy to fix it, both at work and here fixing bugs. Anyway. Almost like you said, but better written in dv/dt form, like dv/dt=a, where 'a' is the acceleration (F/m). Solving this finding v(t), and next integrating to get the position deltas is the key…

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