int doSomething(int num1, int num2); //function prototypes
int main(int argc, char* argv[])
{
int num1, num2;
cout << "Enter number 1: ";
cin >> num1;
cout << "Enter number 2: ";
cin >> num2;
cout << endl;
int ans = doSomething(num1, num2); //assigns what
//the function returns
cout << "The answer is: " << ans << "."; //to ans
getch();
return 0;
}
int doSomething(int num1, int num2)
{
return num1(sqrt(num2))+(num1+num2);
} Help With Functions
June 06, 2002 08:57 AM
I''m very new to C++, and I''m having some problems that I can''t solve by looking in my text book. I can''t figure out what''s wrong with my simple program. Here''s the source code:
When I try to compile this, my compiler gives me the error "[C++ Error] Learning1.cpp(34): E2314 Call of nonfunction." Any help here? I''ve never come across that error before and I don''t know how to fix it.. Thanks!
-Kevinator
136
June 06, 2002 09:05 AM
The compiler thinks:
''return num1(sqrt(num2))+(num1+num2);''
is a function call. Remove the ''num1'' bit and it should ''do something''
''return num1(sqrt(num2))+(num1+num2);''
is a function call. Remove the ''num1'' bit and it should ''do something''
<a href="http://www.purplenose.com>purplenose.com
June 06, 2002 09:05 AM
I tried it out on mine and all it says is that getch() and sqrt() are undecalred. What are you using to compile?
2,211
June 06, 2002 09:06 AM
Your problem is this line:
You are trying to use num1 as if it were a function, which it clearly isn''t. You probably mean
return num1(sqrt(num2))+(num1+num2); You are trying to use num1 as if it were a function, which it clearly isn''t. You probably mean
return num1*(sqrt(num2))+(num1+num2);
158
June 06, 2002 09:08 AM
In:
It thinks you''re calling a function called num1();... Look at how you have it set up. You need some sort of operator between num1 and the opening paren ''(''. That''ll fix it. ex:
and you don really need the parens and could just use:
Gamer-Insight.com
return num1(sqrt(num2))+(num1+num2); It thinks you''re calling a function called num1();... Look at how you have it set up. You need some sort of operator between num1 and the opening paren ''(''. That''ll fix it.
ex:return num1*(sqrt(num2))+(num1+num2); and you don really need the parens and could just use:
return num1*sqrt(num2)+num1+num2; Gamer-Insight.com
June 06, 2002 09:09 AM
Hmm, I added a ''*'' after the first num1 and that did the trick. BTW I''m using Borland C++Builder..
June 06, 2002 09:11 AM
Wow, I go to type my reply and 5 other people reply in the mean-time. Thanks for all the help.
Thanks for all the help.
128
June 06, 2002 09:13 AM
BTW, to the AP: include < math.h >, this is where sqrt () is defined, and include < stdio.h > for getch ().
[edited by - Melraidin on June 6, 2002 10:34:44 AM]
[edited by - Melraidin on June 6, 2002 10:34:44 AM]
This topic is closed to new replies.
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