Could anyone tell me a function that would let me round a number to the nearest 25. I''m using Dev c++ if that makes a differnce. Thanks in advance.

cast it as int! divide by 25 and multiply by 25! should go?

No that isn't what I mean. For example if the user enters a 28 the will automatically be rounded down to 25, if the user enters 46 it is rounded up to 50. I need a function to do this automatically so that the program can process it depending on what value the user inputs.
Thanks.

[edited by - ank2 on April 23, 2002 4:18:25 PM]

function RoundTo25(Value:Double):Integer;begin     Result:=Round(Value/25)*25;end; 

Thanks but i'm using C. I tried translating it but I can't. Is there a similar way to do this in C? Is there a similar function to the Round function you showed for C?

[edited by - ank2 on April 23, 2002 4:48:03 PM]

Well, I don''t know that C++ has a round() function, but to translate that code, it''s like this:

float RoundTo25(double d)
{
return (Round(d/25))*25;
}

If thispost = 0 Then
GoBack()

Else
Read()
End If

Try something like this:

Doesn''t anyone test the code they post?




roundTo( 25, 0 ) == 0
roundTo( 25, 25 ) == 25
roundTo( 25, 26 ) == 25
roundTo( 25, 44 ) == 50
roundTo( 25, 1234 ) == 1225

etc.

ya. the other ones were wrong.

it''s just, as the guy said above:

rounded = int((num + .5 )) / 25 * 25

This works very well, thanks everyone for your help.