lets say i have: ------------------------------------------------------------------- int pointer; int array[20]; pointer = array; ------------------------------------------------------------------ How do i find out the size of the array variable by just using the pointer variable. I thought it was sizeof(*pointer), but that seems to work only for a non-array.

If you have:

int pointer;int array[20];pointer = array; 

You can''t find the size of th array (but you already know it anyways).

Now, if you had:

int *ptr; // note the *!int *array;// array is initialized to some size using either new or mallocp = array; 

You still can''t find the size of the array using the pointer alone. In fact, you can never find the size of the array unless you have a special "marker" element to signify the end, or you store the array size somewhere.

For all of your simple-to-intermediate array needs in C++, I suggest you use std::vector (part of the Standard Template Library, STL). See the STL link in my .sig for more info. For all of your simple-to-intermediate string needs, use std::string. Same link.

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Thanks to Kylotan for the idea!