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3d vector question

Started by November 04, 2001 03:56 PM
3 comments, last by evilchicken 23 years, 3 months ago
Hi, given yaw, pitch and roll, how do I find the 3d vector of x magnitude? Many Thanks.
Depends on what your starting vector is.

If you want your starting vector to be looking down the z axis..then the resultant pyr vector is.

f32 cosP,sinP,cosY,sinY,PYRVec[3];
cosP = cosf(pitch);
sinP = sinf(pitch);
cosY = cosf(yaw);
sinY = sinf(yaw);

PYRVec[0] = cosP * sinY;
PYRVec[1] = -sinP;
PYRVec[2] = cosP * cosY;

Roll isnt calculated into the above because it is not needed for the beginning lookat. PYRVec now contains the normalized direction, so you can now multiply in the magnitude x.


PYRVec[0] *= x;
PYRVec[1] *= x;
PYRVec[2] *= x;


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yeah the starting vector would be looking down the z axis

the angles, yaw, and pitch are relative to the starting vector right?

yup.
thanks =D

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