Why would it fail? Wouldn't it just do nothing? Or is it because v.size()-1 presumably is unsigned since it's being compared against a size_t so it would run MAX_INT times?
Tristam MacDonald. Ex-BigTech Software Engineer. Future farmer. [https://trist.am]
i < size()-1. The last element won't get counted for. And of course, if size() returns 0, it will evaluate to a very large number.
for x in a:
for y in a:
# Do something with x[0] ... y[1]
#A short time later...
for x in a:
#Do something else x[0] .... y[1]
if(x % 1 === 0)
function Vector(const X, Y, Z: Double): TVector;
begin
Result := Vector(X, Y, Z);
end;
“If I understand the standard right it is legal and safe to do this but the resulting value could be anything.”
