How do you create a pointer to a function? I think I saw this explained once but I can''t find where it was

I asked some stuff about function pointers a few days ago. Here is a link to the posts.
Click me Somebody said how to make them in there.

---

Drakonite

[Insert Witty Signature Here]

This way:

RETURN_TYPE (FUNCTION_NAME)(PARAMETERS_TYPE)


Example:

int Foo(int i);
int Foo2(int i);


int (pFunc)(int);

pFunc=Foo;

pFunc(69);//Execute Foo()

pFunc=Foo2;

pFunc(666);//Execute Foo2



What the hells!

Great, that helps a lot.

Another question though...

How would I pass that pointer to a function?
What I am trying to do is pass a pointer to a function - to a function like this:

Create(WINDOW, etc, etc, etc, POINTER_TO_A_FUNCTION)
{
variable_to_receive_function_pointer = POINTER_TO_A_FUNCTION;
// etc
}

This way I can have a class store the pointer to this function and call that function whenever I need it.

Can anyone give a straight example of how I would denotate that? The function will ALWAYS return void and will ALWAYS have no parameters

The easiest way:

typedef void (*function_ptr)(void);create(... , function_ptr fp, ...){ variable_to_receive_ptr = fp; // call function: variable_to_receive_ptr();}