version : October 2000 location : Platform SDK/User Interface Services/Windows User Interface/Windowing/Messages and Messages Queues/About/Handling/Message Loop quote :

MSG msg; while( GetMessage( &msg, NULL, 0, 0 ) != 0 && GetMessage(&msg, (HWND) NULL, 0, 0) != -1) { TranslateMessage( &msg ); DispatchMessage( &msg ); }

should it be replaced by this: ?

MSG msg; int rtn; while(1) { rtn = GetMessage(&msg, NULL, 0, 0); if (rtn == 0 || rtn == -1) break; TranslateMessage( &msg ); DispatchMessage( &msg ); }

cause i wonder(sure) if the code quoted from MSDN will get one extra msg from MsgQueue am i right? M$ sux? ------------------------------ Dedicate to nobody, I''m nobody

No you are wrong. There is no problem with that code. You can replace it to yours, it won`t make a difference.


Both piece of code will exit if the return of get message is 0(WM_QUIT) or -1(I don''t what it is)

There''s a big difference between the two pieces of code... The first one will get *two* messages and throw away the first one.

Looks like a bug to me.

-Mike

Looks like they''ve fixed it in newer MSDN''s actually.

http://msdn.microsoft.com/library/default.asp?URL=/library/psdk/winui/messques_47n4.htm

-Mike

And better yet, when the first GetMessage receives -1 (an error occured) and the second receives 0 (WM_QUIT) the while statement will continue to be executed.


- Houdini