Just use the number that corresponds to the character in a printf() statement:

printf("this is a \225eta version\n");

would read "this is a Beta version"

The \nnn will give you the ascii character for the value.

Otherwise you can do:

printf("This is a %ceta version\n", 225);

where %c is 225 turned into a char representation.

\225 will NOT print the ASCII character #225. Rather, it will print #149, because \ooo is the escape sequence to write octal numbers.

Dunno where you got that \nnn thing. It's not in ANSI C. If it's a part of ANSI C++ then I apologize

So I suggest to spheltem to use \xhh instead, which lets you write a hex byte. For character #225 you would write "\xe1"

If i wished to display the ascii characters i would write an algorith of:

for(char c=0;c<256;c++)cout << c;

that would display all 256 ascii characters

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-PoesRaven

First of all, in case you need to know, I'm using Visual C++ 6.0 and am making a Win32 app with no Direct X. Well, my question is how do you display ASCII text? I can get the 1st 175 ASCII characters by putting it directly into the compiler's editor by holding alt and then putting in the ASCII code but beyond that it doesn't seem to work at all. How do you display ASCII characters beyond 175?

Thanks.

You're right .. /nnn will do octal -- my mistake. I would have used /xhhh for hex, but didn't want to explain the hex part.. yes, use the /xhhh and give the hexadecimal notation for the number.