I have a word what is I want to write a number (let's say 5) but, after the 4th byte 0x0000000000000000 0x000000000000|000 Starting here 0x0000000000101000 To get this ? (It's something with the << or >> operators) Edited by - SKSlayer on January 21, 2001 11:12:34 AM

  WORD var;var = 5;var << 3;  

"Yo yo ma"
-Kramer

btw Ox denotes a hexidecimal number

http://members.xoom.com/myBollux

just in case you don''t know, you can use << or >> to multipy or divide numbers by powers of 2 alot faster than normal multuplying or dividing.

ie:

5<<3 == 5*2^3 == 5*8 == 40
7<<4 == 7*2^4 == 7*32 == 224
2>>2 == 2/2^2 == 2/4 == .5 (0 in binary, last bit lost)
6>>0 == 6/2^0 == 6/1 == 6

Hi smart_idiot,

Modern compilers will optimise that for you anyway, it just serves to make your code a little bit less clear nowdays. Plus they are not limited to powers of 2. i.e. multiplying by 5 will optimise into a left-shift by 2, then adding the original value.

Never underestimate your compiler, it knows all of the tricks, and has (probably) been doing them longer than you

This is still a very useful trick if you write assembly routines though.

Dan

Edited by - danbrown on January 22, 2001 3:43:23 PM

The compiler (mine anyways) only does that if the number your multiplying is A) constant or will never be changed, and B) is a power of two.

I need to turn on optimization for that to work, and I usually don''t bacause it is slower when I am debugging my programs, the trial and error way.

Oh, and I have been programing since I was about 11, so I have been doing it longer than my current compiler, but I have to admit that it does it faster and better that I ever could.

Besides, who doesn''t like showing off their really cryptic code?