how do i get this math out to good c++ code? for example: in*Óranta^years where Ó go from x to y ??

More info is needed...

Is this a summation of the form a * b ^ c where b goes from x to y , which are integer values? If so, you can use the pow() function to calculate b ^ c , and a for loop to do the overall summation.

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int Agony() { return *((int*)0); } Mwahaha... >8)

yes this is a summation...

for example:

a* summation of (b)^n where n goes from x to y..

any nice example?

  int result;  for(int n=x;n<y;n++){    result=a*pow(b,n);  };

why not just use the formula for the summation of a geometric series
(1-r^n )/(1 - r)

this way you would have to use pow() at most 2 times.

in case want to use the loop & you want this:

"a* summation of (b)^n where n goes from x to y..."

don''t use penguins, use this...

    int sum = 0;    for( int n=x ; n <= y ; n++ ) {        sum += pow( b, n );    }    int result = a * sum; 

there are subtle differences : )