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Quadratic Path

Started by May 04, 2003 03:10 PM
5 comments, last by piknic 21 years, 9 months ago
I was wondering if someone could give me code ( actual or just explanation ) on how to, after user puts in three values ( a,b and c..for the euqation ax^2+bx+c) , to make a picturebox follow this line.. For example say my equation is y=x^2.. How would i make a picture box follow this curve (preferably using a timer since i want it to go relatively slow). I need some explantion on how to do this.. Like i need the pic1.Left = whatever and pic2.Top = w/e... ( im new at this and im sure that is very dumb and wont work and must be much more complex).. Either way some example code with good explantion would help..Or if it is that simple please tell em Thanks
y = a*x*x + b*x + c.

Just increment x by a little bit each time, and calculate the y value through the equation. Then draw your picture at (x,y).
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ok..thanks..oh and btw...How do u do (x,y)..rly i have no idea how to make a picture box have a point on the form without doing .top and .left lol...whats an example of code saying X = 2 and Y = 4.. What would i use to draw the picture box on the form.??
I think your best bet would be using C++.
You know what I never noticed before?
quote:
Original post by vanillacoke
I think your best bet would be using C++.


Hmm, why?

Piknik: what language are you using? You mention forms, so I assume you are using some sort of RAD language, like VB, Delphi or C++Builder, correct?
Here's some Delphi code that will do your job:


    Function Quadratic (Parameter : Integer) : Integer;Var    Temp : Integer;Begin    { Form AX^2 + BX + C }    Temp := (Parameter * Parameter) + (5 * Parameter) + 2;    Result := Temp;End;Procedure MovePicture (Var Image : TImage);Var    Loop, QuadraticResult : Integer;Begin    While True Do Begin        If Loop = 100 Then Begin            Loop := 0;        End;        QuadraticResult := Quadratic (Loop);        Inc (Loop);        Image.Left := Image.Left + QuadraticResult;        Image.Right := Image.Right + QuadraticResult;        Image.Bottom := Image.Bottom + QuadraticResult;        Image.Top := Image.Top + QuadraticResult;    End;End;    


I haven't tested that, mind.
Edit: fixed type inconsistencies.

[edited by - MDI on May 5, 2003 4:29:12 PM]
Unless of course you want it to move at a uniform speed along your function, in which case the math (and programming) gets much more interesting I won''t go into it unless that''s what you want though...
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using VB

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