Hi all.. I've written this very simple example of what goes wrong in my prog. that I don't seem to get.

#include <iostream.h>

#define MODE1 = 1;
#define MODE2 = 2;
#define MODE3 = 4;
#define MODE4 = 8;

int main()
{
	unsigned char Mode = 5;
	if (Mode & MODE1 == MODE1)
	{cout << "Mode 1 ";}
	if (Mode & MODE2 == MODE2)
	{cout << "Mode 2 ";}
	if (Mode & MODE3 == MODE3)
	{cout << "Mode 3 ";}
	if (Mode & MODE4 == MODE4)
	{cout << "Mode 4 ";}
	return 0;
}
  

What's wrong? Thanx, Marty [edited by - Marty666 on March 19, 2003 1:27:55 PM]

What do you want to happen and what is happenning..

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you may want to remove those equal signs ''='' from the defines ... that''s the only error i can find....

What I want to happen is: If I put 1 in ''Mode'' it only writes "Mode1" to the screen...
If I put in 2, "Mode2 "
... 3 "Mode1 Mode2 "
... 4 "Mode3 "
... 5 "Mode1 Mode3 "

It''s like 8 flags in the unsigned char. I''ve got a 4 flags in this example (MODE1 to MODE4) which i defined. With a logical AND I want to check if this mode is activated. (If the correct bit is set to 1). To check this, I have the example write "Mode# " to the screen... I use 5 in the example so it should say "Mode1 Mode3 "

Thanx, Marty


PS: This is what c++ tells me:


Compiling...
andtest.cpp
error C2059: syntax error : ''=''
error C2143: syntax error : missing '';'' before ''==''
error C2143: syntax error : missing '';'' before '')''
error C2143: syntax error : missing '';'' before ''{''
error C2059: syntax error : ''=''
error C2143: syntax error : missing '';'' before ''==''
error C2143: syntax error : missing '';'' before '')''
error C2143: syntax error : missing '';'' before ''{''
error C2059: syntax error : ''=''
error C2143: syntax error : missing '';'' before ''==''
error C2143: syntax error : missing '';'' before '')''
error C2143: syntax error : missing '';'' before ''{''
error C2059: syntax error : ''=''
error C2143: syntax error : missing '';'' before ''==''
error C2143: syntax error : missing '';'' before '')''
error C2143: syntax error : missing '';'' before ''{''
Error executing cl.exe.

andtest.exe - 16 error(s), 0 warning(s)

yep,..... it's those equal and ';' characters in your defines

do this:-

#define MODE1 1
#define MODE2 2
#define MODE3 4
#define MODE4 8

[edited by - Crawl on March 19, 2003 1:40:15 PM]

Ok, I removed the = signs... Now it gives 12 errors:

Compiling...
andtest.cpp

error C2143: syntax error : missing '')'' before '';''
warning C4390: '';'' : empty controlled statement found; is this the intent?
error C2143: syntax error : missing '';'' before ''==''
error C2059: syntax error : '')''
error C2143: syntax error : missing '')'' before '';''
warning C4390: '';'' : empty controlled statement found; is this the intent?
error C2143: syntax error : missing '';'' before ''==''
error C2059: syntax error : '')''
error C2143: syntax error : missing '')'' before '';''
warning C4390: '';'' : empty controlled statement found; is this the intent?
error C2143: syntax error : missing '';'' before ''==''
error C2059: syntax error : '')''
error C2143: syntax error : missing '')'' before '';''
warning C4390: '';'' : empty controlled statement found; is this the intent?
error C2143: syntax error : missing '';'' before ''==''
error C2059: syntax error : '')''
Error executing cl.exe.

andtest.exe - 12 error(s), 4 warning(s)

k, now remove the '';'' from your #define statements:

this is BAD #define FOO 4;

this is GOOD #define FOO 4

#define is a pre-compiler directive. it''s not a normal line of c-code. you DON''T end it with a semi-colon

-me

unsigned char Mode = 5;

that does not equal 'Mode'

Please visit Turt99 Productions

EDIT: What I'm trying to get at is why is your varible mode a char? and then are you wanting to add the 2 variables?

[edited by - Turt99 on March 19, 2003 1:49:37 PM]

Thanx! It looks like this now...

#include <iostream.h>#define MODE1  1#define MODE2  2#define MODE3  4#define MODE4  8int main(){	unsigned char Mode = 1;	if (Mode & MODE1 == MODE1)	{cout << "Mode 1 ";}	if (Mode & MODE2 == MODE2)	{cout << "Mode 2 ";}	if (Mode & MODE3 == MODE3)	{cout << "Mode 3 ";}	if (Mode & MODE4 == MODE4)	{cout << "Mode 4 ";}	return 0;} 

One problem left: My output is:
"Mode1 Mode2 Mode3 Mode4 " whatever i put in Mode...

Marty

remove the semicolons from the defines