sending a 2d Array to a funktion? help
February 14, 2003 02:10 AM
I need to send a 2d Array to a funktion andI have no clue how,
could somebody help me?
127
February 14, 2003 02:15 AM
void myfunction(array[size][])
It''s funky but it works
It''s funky but it works
The nightmare travels across the cosmos with his burning mane. The trail of ash that is produced.
?Have a nice day!?
134
February 14, 2003 03:15 AM
you can do this
example:
void funcx(int *array)
{
int f,j;
for(j=0;j<=100;j++)
f = array[1][j]; //you can access the array like this
}
int a[100][100];
main()
{
funcx(a); //passing array to function
return 0;
}
[edited by - lone_ranger on February 14, 2003 4:15:32 AM]
[edited by - lone_ranger on February 14, 2003 4:16:28 AM]
example:
void funcx(int *array)
{
int f,j;
for(j=0;j<=100;j++)
f = array[1][j]; //you can access the array like this
}
int a[100][100];
main()
{
funcx(a); //passing array to function
return 0;
}
[edited by - lone_ranger on February 14, 2003 4:15:32 AM]
[edited by - lone_ranger on February 14, 2003 4:16:28 AM]
Virtus junxit, mors non separabit
432
February 14, 2003 04:29 AM
It kind of depends on your language of choice. If you''re using Java, for instance, the array itself know how big it is - and you could do the following:
But if you are using C or C++ you need to pass along the size of the array too - like this:
-+-+-+-+-+-+-+-+-+-+-+-+-+-+-
Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius -- and a lot of courage -- to move in the opposite direction.
public void arrayFunction( int[] theArray ){ for( int i = 0; i < theArray.length; i++ ) { System.out.println( "theArray[i]: " + theArray[i] ); {} But if you are using C or C++ you need to pass along the size of the array too - like this:
void arrayFunction( int * theArray, int arraySize ){ int i; for( i = 0; i < arraySize; i++ ) { printf( "theArray[i]: %i", theArray[i] ); }} -+-+-+-+-+-+-+-+-+-+-+-+-+-+-
Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius -- and a lot of courage -- to move in the opposite direction.
"We confess our little faults to persuade people that we have no large ones." -Francois de La Rochefoucauld (1613 - 1680). | My blog
199
February 14, 2003 08:38 AM
the function''s parameters should be like so:
rtype function(type array[][numOfCols], int size);
this may work too:
rtype function(type **array, int rows, int cols);
hope that helps.
rtype function(type array[][numOfCols], int size);
this may work too:
rtype function(type **array, int rows, int cols);
hope that helps.
276
February 14, 2003 09:51 AM
You can also send the function a single, very long array. For example if you want an array of size [200][200] you would declare it like int myArray[200*200]. You could then access it like so:
Andre LaMothe does this in his TOTWGPG book (though not for the same reason; he does it to access the memory... or something :D)
Peon
for (int j = 0; j < 200; j++){ for (int i = 0; i < 200; i++) { cout<<myArray[i+200*j]; }} Andre LaMothe does this in his TOTWGPG book (though not for the same reason; he does it to access the memory... or something :D)
Peon
Peon
432
February 14, 2003 11:00 AM
WOW, I entirely missed the fact that it was a 2d array.....my bad....
-+-+-+-+-+-+-+-+-+-+-+-+-+-+-
Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius -- and a lot of courage -- to move in the opposite direction.
-+-+-+-+-+-+-+-+-+-+-+-+-+-+-
Any intelligent fool can make things bigger, more complex, and more violent. It takes a touch of genius -- and a lot of courage -- to move in the opposite direction.
"We confess our little faults to persuade people that we have no large ones." -Francois de La Rochefoucauld (1613 - 1680). | My blog
140
February 14, 2003 11:15 AM
I had to use this when I calloc''ed a multidimensional array...
Am I to assume I was correct in this usage?
for (int j = 0; j < 200; j++){ for (int i = 0; i < 200; i++) { cout<<myArray[i+200*j]; }} Am I to assume I was correct in this usage?
199
February 14, 2003 01:15 PM
quote: Original post by Peon
You can also send the function a single, very long array. For example if you want an array of size [200][200] you would declare it like int myArray[200*200]. You could then access it like so:
Andre LaMothe does this in his TOTWGPG book (though not for the same reason; he does it to access the memory... or something :D)
Peon
This would simply make the array 1D but the same size as the 2D. LaMothe does this when accessing a DirectDraw videobuffer because DirectDraw guarantees a linear videobuffer. Hence, you need to access it as if it were a 1D array.
[edited by - Arkainium on February 14, 2003 2:16:57 PM]
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