yeah. I was about to say what eric just did... no matter where you apply force to an object, it's momentum at it's centre of mass will always increase by the same amount.
As for the rotation, it's easy too.. I'm assuming your using a matrix to rotate and translate the object, well, to get the angular accleration to apply to the matrix, simply cross the force vector with the normal vector from the impact to the centre of mass... (divided by the mass it'self).. This will give you the axis that the rotation occurs on (and hence when you rotate a matrix, you rotate around an axis, it makes it all the easier)
[edited by - RipTorn on October 29, 2002 4:57:05 AM]
torque and linear forces
Ok, Thanks alot guys!
--------------------------------------------------------------If it sounds like a good idea, do it. It is much harder to get permission than it is to apologize.
October 29, 2002 09:25 AM
F = force
R = Relative pos of force to the body
L = Linear momentum += F
T = Torque += R X F
R = Relative pos of force to the body
L = Linear momentum += F
T = Torque += R X F
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