Found the bug!

ok guys! We certainly missed this one! After I eliminated the return sentence I still couldn''t get the program to display the map in the correct way. After a little nap, though, I got it: the right way to pass the data from the sequential array to the two dimensional one is the following:

for(int j=0; j<60; j++)
for(int i=0; i<144; i++)
iMap[j]=buffer[i+(j*144)];

Yes, I know! Rediculous error. But what the hell. I''ve accepted the fact that I am no genious long time ago! Thanks for your time to reply, anyway.

Is it just me, or will this not work.
for(int j=0; j<60; j++) // it counts to 59
for(int i=0; i<144; i++) // it counts to 143
iMap[j]=buffer[i+(j*144)]; // assigns 143 + 59*144 to iMap[59]

Shouldn't it be:

for(int j=0; j<60; j++)
{
for(int i=0; i<144; i++)
iMap[j]=buffer[i+(j*144)];
}

Wouldn't this be the way to update each element?

Edited by - grandmlee on January 22, 2002 6:58:27 AM

quote: Original post by GrandMLee

  Is it just me, or will this not work.for(int j=0; j<60; j++)  // it counts to 59for(int i=0; i<144; i++) // it counts to 143iMap[i][j]=buffer[i+(j*144)]; // assigns 143 + 59*144 to iMap[59]  

Shouldn''t it be:

  for(int j=0; j<60; j++)    {   for(int i=0; i<144; i++)   iMap[i][j]=buffer[i+(j*144)];   }  

Wouldn''t this be the way to update each element?


No, both of them are identical


This

  for(int x=0; x<3; x++) for(int y=0; y<3; y++)  for(int z=0; z<3; z++)   function(x,y,z);  

is the same as this

  for(int x=0; x<3; x++){ for(int y=0; y<3; y++) {  for(int z=0; z<3; z++)  {   function(x,y,z);  } }}  

This is because a for statement treats the next line as a set of parentheses. This is the same as a while


you can do this for example
for(int x=0; x<3; x++);
or this
for(int x=0; x<3; x++){}
and they will both just make x count to 3.



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yeah, I realized that as I was almost drifting off to sleep. I must have been tired yesterday or something.