It seems if I have two try/catch blocks in a row in a function, the second one doesn't seem to catch anything. For example, this script:

void main() {
    try { throw ("1"); }
    catch { print ("Exception 1"); }

    try { throw ("2"); }
    catch { print ("Exception 2"); }

    try { throw ("3"); }
    catch { print ("Exception 3"); }
}

prints only this:

Exception 1
2

So the first exception is caught and handled correctly, and the second one aborts the script (which prints the aborting exception, in my case, so you see the "2").

Thanks for the report. I'll investigate and correct this

I've fixed this in revision 2579.

I'm sorry for the delay.

Thanks!