do you know this water jug problem
you have two jugs,3 gallon one and 4 gallon one ,doesn't have any markers on it,you fill this jugs with pump,how to fill 2 gallons of water in 4 gallon jug?
anybody know answer plz reply..
What does this have to do with artificial intelligence?
I've heard variations of this puzzle before.
Interestingly (is that a word?), I don't think ai would have much trouble solving this problem (genetic algorithms/minimax would solve this easily).
1st solution: Fill the 3 gallon jug, and pour it into the 4 gallon jug.
Fill the 3 gallon jug again and begin pouring it into the 4 gallon jug but stop when the 4 gallon jug is full.
There is another solution but it's not perfect because it depends on the dimensions and mass of the jugs:
Fill the 4 gallon jug and pour it into the 3 gallon jug till there is one gallon left. Empty the 3 gallon jug, and pour the 1 gallon into it.
Fully fill the 4 gallon jug, then submerge the 3 gallon jug in it so the tops are level - it will displace roughly 3 gallons and there will be 1 gallon left in the large jug. Step 3: Profit!
Edit: Just thought of another solution:
Fill the 4 gallon jug and pour it into the 3 gallon jug till there is one gallon left. Empty the 3 gallon jug, and pour the 1 gallon into it.
Fully fill the 4 gallon jug, then pour it into the 3 gallon jug till it is full. There is now 2 gallons left.
I've heard variations of this puzzle before.
Interestingly (is that a word?), I don't think ai would have much trouble solving this problem (genetic algorithms/minimax would solve this easily).
1st solution: Fill the 3 gallon jug, and pour it into the 4 gallon jug.
Fill the 3 gallon jug again and begin pouring it into the 4 gallon jug but stop when the 4 gallon jug is full.
There is another solution but it's not perfect because it depends on the dimensions and mass of the jugs:
Fill the 4 gallon jug and pour it into the 3 gallon jug till there is one gallon left. Empty the 3 gallon jug, and pour the 1 gallon into it.
Fully fill the 4 gallon jug, then submerge the 3 gallon jug in it so the tops are level - it will displace roughly 3 gallons and there will be 1 gallon left in the large jug. Step 3: Profit!
Edit: Just thought of another solution:
Fill the 4 gallon jug and pour it into the 3 gallon jug till there is one gallon left. Empty the 3 gallon jug, and pour the 1 gallon into it.
Fully fill the 4 gallon jug, then pour it into the 3 gallon jug till it is full. There is now 2 gallons left.
Quote: Original post by stevenmarky
What does this have to do with artificial intelligence?
I've heard variations of this puzzle before.
Interestingly (is that a word?), I don't think ai would have much trouble solving this problem (genetic algorithms/minimax would solve this easily).
Why? Why? whyyyyyy would you use genetic algorithms to solve a problem like that? Strong basics, guys. Even minimax is innapropriate. Simple state representation, very few actions possible, no good scoring/heuristic possible, solution is very short: this is the job for a simple breadth-first search.
Quote: Original post by SteadtlerWhy? Why? whyyyyyy would you use genetic algorithms to solve a problem like that? Strong basics, guys. Even minimax is innapropriate. Simple state representation, very few actions possible, no good scoring/heuristic possible, solution is very short: this is the job for a simple breadth-first search.
That's my opinion too. If you prefer solutions that don't waste a lot of water, use Dijkstra's algorithm (very similar to breadth-first search).
Quote: Original post by Steadtler
Why? Why? whyyyyyy would you use genetic algorithms to solve a problem like that? Strong basics, guys. Even minimax is innapropriate. Simple state representation, very few actions possible, no good scoring/heuristic possible, solution is very short: this is the job for a simple breadth-first search.
You're right, GAs aren't appropriate for this. So I guess NNs must be the way to go. [grin]
Die Hard 3, FTW.
I've had this come up in school, during an interview, and even as a puzzle in a D&D campaign. There's really no trick to it, just brute force your way to a solution. Either way you go (which jug you start with, I mean) will get you there.
I've had this come up in school, during an interview, and even as a puzzle in a D&D campaign. There's really no trick to it, just brute force your way to a solution. Either way you go (which jug you start with, I mean) will get you there.
Without order nothing can exist - without chaos nothing can evolve.
Quote: Original post by CyberSlag5k
Die Hard 3, FTW.
I've had this come up in school, during an interview, and even as a puzzle in a D&D campaign. There's really no trick to it, just brute force your way to a solution. Either way you go (which jug you start with, I mean) will get you there.
Wow. Im no big fan of puzzle questions in interviews, I would avoid like the plague any business that ask such a cliché puzzle.
Cheers to Sneftel who is trying to raise my temper :P
I guess I just meant any brutish force algorithm would solve this easily.
Shutup!
Well anyway, I have a generic minimax algorithm which could be applied to this problem easily (you could also set the amount of players, in this case it would be one).
Quote:
Why didn't you say that then?
Shutup!
Well anyway, I have a generic minimax algorithm which could be applied to this problem easily (you could also set the amount of players, in this case it would be one).
Quote: Original post by stevenmarky
I guess I just meant any brutish force algorithm would solve this easily.Quote:
Why didn't you say that then?
Shutup!
Well anyway, I have a generic minimax algorithm which could be applied to this problem easily (you could also set the amount of players, in this case it would be one).
How would you score each "board" for minimax? Quantity of water in each jug is no indication of or close you are to "winning"
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