Quote: Original post by kaysik
winexec always worked for me

(and he wants to run a .exe so I'm pretty sure he's after windows functions not *nix)

Quote: Original post by SirKnight
If you called CreateProcess( "prog.exe", filename, etc... ) then filename would be argv[1] without a doubt. argv[0] is always the process name, so the first command line arg passed is argv[1], the next is argv[2] and so on.


-SirKnight

Quote: MSDN
If both lpApplicationName and lpCommandLine are non-NULL, the null-terminated string pointed to by lpApplicationName specifies the module to execute, and the null-terminated string pointed to by lpCommandLine specifies the command line. The new process can use GetCommandLine to retrieve the entire command line. Console processes written in C can use the argc and argv arguments to parse the command line. Because argv[0] is the module name, C programmers generally repeat the module name as the first token in the command line.

#include <iostream>#include <windows.h>using namespace std;int main() {	char filename[20] = "inputfile";	char *cmd = new char[80];	cmd[0] = 0;	strcat( cmd, "shouldbeprocessnameright? " );	strcat( cmd, filename );	STARTUPINFO si = { 0, };	si.cb = sizeof( si );	PROCESS_INFORMATION pi = { 0, };	CreateProcess( "..\\test31\\Debug\\test31.exe", cmd, NULL, NULL, FALSE,		NORMAL_PRIORITY_CLASS | CREATE_NEW_CONSOLE, NULL, NULL, &si, &pi );	delete [] cmd; // ZOMG! ZOMG! I almost forgot...	cin.get();	return 0;}

#include "stdio.h"#include <process.h>int main( int argc, char *argv[] ) {	if ( argc == 2 ) {		puts( argv[0] );		puts( argv[1] );	}	system( "pause" );	return 0;}

Quote: shouldbeprocessnameright?
inputfile
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