after using gluPerspective(60.0f,(GLfloat)800/(GLfloat)600,0.1f,100.0f) in a 800 x 600 window, how to draw a quad that with it's top-left point at the top-left point of the window screen? how to calculate it, thank you? [edited by - silversaraph on February 7, 2004 8:17:35 PM]

Highest visible point in frustrum at distance d:

[1] y = tan(fovy) * d

Leftmost visible point in frustrum at distance d:

[2] x = -tan(fovx) * d

You already have fovy. To calculate tan(fovx):

[3] fovy = atan(height / distance)[4] fovx = atan(width / distance)[5] tan(fovy) = height / distance (rearrangement of 3)[6] tan(fovx) = width / distance (rearrangement of 4)[7] distance = height / tan(fovy) (rearrangement of 5)[8] tan(fovx) = width / (height / tan(fovy)) (7 into 6)[9] tan(fovx) = (width * tan(fovy)) / height (rearrangement of 8)[10] tan(fovx) = tan(fovy) * (width / height) (rearrangement of 9)

Enigma

Thank you Enigma, I will try it out

Enigma, out of curiosity why didn''t you recommed glOrtho? Just curious.

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My nothing-to-write-home-about OpenGL webpage. (please pardon the popups!)

It was late and I read his post and just assumed he really wanted to be able to position something at an absolute position under a perspective projection. Reading it again it''s quite possible that an orthographic projection would have been the simplest answer. Just goes to show that if you''re not careful how you specify your question you might not get the best answer!

Enigma