How would I do this? I have a var: float **ins; that I want to hold an array of pointers to floats. How can I do this using the new command? My initial thought was to do soething like: ins = new (float*)[numofins]; but the compiler doesn''t like that at all I did look in MSDN btw, and I found how to do it like this: float *ins[3]; but that doesnt help much thanx! tazzel3d ~ dwiel

you were almost right what you actually want is ins = new float *[number of float pointers];

eg

float **a;a = new float *[20]; 

to initialise the pointers in the array you could do

for(int i = 0;i < 20; i++){a = new float[whatever u like];} 

[edited by - vivi2k on September 19, 2002 8:48:21 AM]

quote: Original post by vivi2k
for(int i = 0;i < 20; i++)
{
a = new float[whatever u like];
}

lol, stupid vb tags it becomes italic :D
anyway, it's not a = new float[whatever u like];
but:

for (int index_i=0; i<20; i++){   a[index_i] = new float [whatever u like];}  

when you do this:
a = new float* [20];
you make 20 pointers, which are not yet initialized, to float data type. These pointers need to be valid, so you initialize each of them:

a[0] = new float [whatever u like];a[1] = new float [whatever u like];... // and so on until index 19  

something like that.

My compiler generates one error message: "does not compile."


EDIT:
Arghh!! Damn tags!

[edited by - nicho_tedja on September 19, 2002 6:07:18 PM]